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**Chapter - 7**

**SQUARES, SQUARE ROOTS, CUBES, CUBE ROOTS**

**Squares:** When the exponent of a base is 2, the numbers obtained are called squares or squared numbers.

**Perfect Square:** A natural number is called a perfect square if it is the square of a number.

1, 4, 9, 16, 25, 36 --------- are the perfect square of the numbers

1, 2, 3, 4, 5, 6 ------------ respectively.

5, 6, 7, 8, 11, 50 and 125 are not perfect square of any natural number.

Examples of Perfect Square

**To determine whether a given number is a perfect square.**

Step I: Express the given number as the product of its prime numbers.

Step II: Express the prime factors as pairs of same number

Step III: Check if there are any unpaired factors

Step IV: If there is no unpaired factor, the given number is a perfect square.

**Properties of Squares:**

1) Squares of even numbers are even.

2) Squares of odd numbers are odd.

3) A number ending with 2, 3, 7 or 8 is never a perfect square. e.g 23, 347, 2818 cannot be perfect squares.

4) A number ending with an odd number of zeros is never a perfect square. Thus 150, 4400000, 48000 cannot be perfect squares.

5) The square of a natural number (other than 1) is either a multiple of 3 or exceeds a multiple of 3 by 1.

6) The square of a natural number (other than 1) is either a multiple of 4 or exceeds a multiple of 4 by 1

7) The difference between the squares of two consecutive natural numbers is equal to their sum.

For example: 2^{2} - 1^{2} = 4 – 1 = 3 which is equal to 2 + 1 = 3

5^{2} - 4^{2} = 25 – 16 = 9 which is equal to 5 + 4 = 9

11^{2} - 10^{2} = 121 – 100 = 21 which is equal to 11 + 10 = 21

__Some interesting facts:__

1) Pythagorean Triplets: For every natural number m (other than 1) there is a triplet such as (2m), (m^{2}-1) and (m^{2}+1)

These triplets are called Pythagorean Triplets. They obey the relation (2m)^{2}+(m^{2}-1)^{2}=(m^{2}+1)^{2}

For m = 2, Pythagorean triplets are 2 x 2, 2^{2}-1, 2^{2}+1 or 4, 3 and 5 and (4)^{2} + (3)^{2} = 5^{2}

For m = 4, triplets are 4 x 2, 4^{2 }- 1, 4^{2 }+ 1

i.e. 8, 15, 17 and 8^{2} + 15^{2} = 17^{2}

and so on it is true for every natural number.

2) The square of any natural number will have either of 0, 1, 4, 5, 6 or 9 at the unit place.

3) The square of a natural number (n) is always equal to the sum of first (n) odd natural numbers.

If x = 4 Then 4^{2} = 1 + 3 + 5 + 7

If x = 6 Then 6^{2} = 1 + 3 + 5 + 7 + 9 + 11

If x = 9 Then 9^{2} = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17

4) If n is a perfect square then 2n can never be a perfect square.

5) A perfect square number is never negative.

__Square Roots__

The square root of a number n is that number which when multiplied by itself gives n as the product. For example: 7 x 7 = 49, So 7 is the square root of 49. It is written as

Finding square root of a perfect square.

**(a) By finding prime factors. **

Example: If the square root of 576 is to be found out we find the prime factors of 576

576 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3

Make pairs of factors and pick up one factor from each pair.

= 2 x 2 x 2 x 3 = 24

**Example:** Simplify

**Solution:** 900 = 30 x 30

0.09 = 0.3 x 0.3 = 0.3

0.003

= 30.303

**(b) Finding the square root by long division method**

**Example1:** Find the square root of 7396

**Solution:**

** **

Step I: Beginning from the right, reduce the digits in pairs from right to left.

Step II: Take the first pair of digits and find the nearest sq. root. The nearest square root of 73 is 8. Write 8 as quotient and also as divisor. Write the product 8 x 8 = 6 below 73 and Subtract.

The remainder is 9

Step III: Bring down the next pair 96. Double 8, the number in the quotient and place the double i.e. 16 as the next divisor. Now 99 divided by 16 is approximately 6. So put 6 with 8 in the quotient also with 16 as the divisor and multiply 166 by 6 and get 996. Now the remainder is zero. So 86 is the exact square root.

Therefore

**Example 2:** Find the sq. root of

**Solution:**

**Finding the number of digits in the square root of a perfect square. **

Rule: If a perfect square contains n digits then, its square root will contain digits if n is even and digits if n is odd.

**Finding square root of a perfect square decimal number by long division.**

While finding the square root of a natural number we make pairs from right to left and if in the last, one digit is left, we leave it by itself. In case of decimal number we make pairs from right to left for the integral part and from left to right for the decimal portion.

If the last period of the decimal number contains only one digit, we add zero to it. The square root of a decimal number will contain as many decimal places as there are pairs in the decimal part of the given number. The method to be followed is the same as for the whole number.

**Example 3:** If = 56. Find the value of +

**Solution:** Since = 56

= 5.6

and = 0.56

∴ + .= 5.6 + 0.56 = 6.16

**Example 4:** Find the value of

If

** Solution:**

**Example 5:** Evaluate

**Solution:** Given expression =

**Example 6**: Evaluate

**Solution:** The sum of decimal places both in the numerator as well as denominator is 6. So we can remove the decimals

**Example 7:** Find the least number which must be added to 4562 to make it a perfect square.

**Solution:**

** **** **

8 x 128 = 1024

If in place of 962 it is 1024 we will get a perfect square so add

1024 – 962 = 62

**Cubes :** A cube of a number, is that number raised to the power 3. The cube of a number is obtained by multiplying it with itself 3 times.

Cube of 5 is 5 x 5 x 5 = 125

Cube of 6 is 6 x 6 x 6 = 216

How to determine whether a given number is a perfect cube

Step 1 Make prime factors of the given number

Step 2 Make groups of the prime factors – a group containing 3 same numbers.

Step 3 Check the ungrouped factor

Step 4 If there is no ungrouped factor, the number is a perfect cube.

**Example:** Is 1728 a perfect cube

**Solution:** Prime factors of 1728 are = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3

The prime factors can clearly be grouped into groups of 3 each and no factor is left ungrouped

So 1728 is a perfect cube.

__Properties of cubes:__

(i) Cube of a natural number is a natural number

(ii) Cube of all even natural numbers are even.

(iii) Cube of all odd natural numbers are odd.

(iv) Cubes of all negative numbers are negative.

(v) For any rational number

(vi) Cube of a natural number, which is a multiple of 3, is a multiple of 27

(vii) Cube of a natural number of the form 3n+1 is also a natural number of the form 3n+1

(viii) Cube of a natural number of the form 3n+2 is also a natural number of the form 3n+2

(ix) Cube of a number, having a zero at the unit place, has three zeros at the end.

For example (10)^{3} = 1000

**Example:** What is the smallest number by which 2400 be multiplied so that the product is a perfect cube?

a) 70 b) 80 c) 90 d) 60

**Solution:** 2400 = 2 x 2 x 2 x 2 x 2 x 3 x 5 x 5

After making the groups of three for each prime number we need one 2’s, two 3’s and one 5.

So we need a number 2 x 3 x 3 x 5 i.e. 90

So option (c) is correct.

__Cube roots: __

A natural number n is a cube root of the number m if m = n^{3}

The symbol for cube root is

To find the cube root of a perfect cube number

Step 1: Make prime factors of the given number

Step 2: Make groups of three each of the prime factors

Step 3: Choose one out of the group of three factors and find their product

Step 4: This product is the required cube root of the given number.

**Example:** Find the cube root of -4096

**Solution:** Prime factors of 4096 are 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

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